C++ Program to Show Number is Even or Odd Without Using Modulus Operator
Write a program to show an inputted no is even or odd without the use of modulus operator.
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Algorithm
- Start.
- Read a number, n
- a= n-2*(int (n/2)).
- If a=0 display “The number is even” else display “The number is odd”
- End
Source Code
#include<iostream>
#include<stdio.h>
#include<conio.h>
using namespace std;
int main()
{
int n,a;
cout<<"Enter a number:";
cin>>n;
a=n-2*(int(n/2));
if(a==0)
cout<<"The number is even"<<endl;
else
cout<<"The number is odd"<<endl;
}
Output
