Write a Program that displays the current monthly salary of chief executive officer, information officer, system analyst and programmer that has been increased by 9, 10,12 and 12% respectively in year 2014. Let us assume that the salary in year 2013 are
- CEO=Rs 35,000 per month
- Information Officer=Rs 25,000 per month
- System Analyst=Rs 24,000 per month
- Programmer =Rs 18000 per month
Make function that takes arguments one salary and other increment use proper default arguments.
Algorithm
- Start
- Define an array salary[4] to store the salary of the posts in the year 2013.
- Define a function new_salary[float sal(i),int inc=0.12] with default value for increment as .12.
- Calculate the new salaries by passing the salary of the old year and the increment rate to the function using the function new salary[sal(i),inc] and print them.
- End of program
- Float new_salary(int sal(i),float inc=0.12)
Source Code
#include<iostream.h>
#include<conio.h>
#include<iomanip.h>
float new_sal(float sal, float inc=0.12);
void main()
{
float sal0=35000,sal1=25000,sal2=24000,sal3=18000;
cout<<"Salary in the year 2013 per month:"<<endl
<<setw(24)<<"Chief executive officer:"<<sal0<<endl
<<setw(24)<<"Information officer:"<<sal1<<endl
<<setw(24)<<"System analyst:"<<sal2<<endl
<<setw(24)<<"Programmer:"<<sal3<<endl;
sal0=new_sal(sal0, 0.09);
sal1=new_sal(sal1, 0.10);
sal2=new_sal(sal2);
sal3=new_sal(sal3);
cout<<endl<<"Salary in the year 2014 per month:"<<endl
<<setw(24)<<"Chief executive officer:"<<sal0<<endl
<<setw(24)<<"Information officer:"<<sal1<<endl
<<setw(24)<<"System analyst:"<<sal2<<endl
<<setw(24)<<"Programmer:"<<sal3<<endl;
getch();
}
float new_sal(float sal, float inc)
{
return(sal+(sal*inc));
}
